x=1+0.5x^2

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Solution for x=1+0.5x^2 equation: 



x=1+0.5x^2

We move all terms to the left:

x-(1+0.5x^2)=0

We get rid of parentheses

-0.5x^2+x-1=0

a = -0.5; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-0.5)·(-1)
Δ = -1
Delta is less than zero, so there is no solution for the equation

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